How to remove server from Multi-tier environment in Zimbra
For Example: We want to remove 2 server from server pool.
- mta1.example.com
- proxy1.example.com
Following are the steps that we need to execute:
1. Check all existing server list :
Run as zimbra users :
$ zmprov gas # It will list all server
2. Login to that server and stop ZCS services
[zimbra@mta1.example.com] $ zmcontrol stop
[zimbra@proxy1.example.com] $ zmcontrol stop
3. Check Process after ZCS service stop
[root@mta1.example.com] # ps -ef | grep -i zimbra | grep -v grep
[root@mta1.example.com] #
[root@proxy1.example.com] # ps -ef | grep -i zimbra | grep -v grep
[root@proxy1.example.com] #
4. Delete or Remove server from COS
[zimbra@ldap.example.com] $ zmprov ds mta1.example.com
[zimbra@ldap.example.com] $ zmprov ds proxy1.example.com
5. Remove server from Logger Services :
[zimbra@ldap.example.com] $ zmloggerhostmap -d mta1.example.com
[zimbra@ldap.example.com] $ zmloggerhostmap -d proxy1.example.com
This article gives an idea about, How to remove server from server pool ?.
For Example: We want to remove 2 server from server pool.
- mta1.example.com
- proxy1.example.com
Following are the steps that we need to execute:
1. Check all existing server list :
Run as zimbra users :
$ zmprov gas # It will list all server
2. Login to that server and stop ZCS services
[zimbra@mta1.example.com] $ zmcontrol stop
[zimbra@proxy1.example.com] $ zmcontrol stop
3. Check Process after ZCS service stop
[root@mta1.example.com] # ps -ef | grep -i zimbra | grep -v grep
[root@mta1.example.com] #
[root@proxy1.example.com] # ps -ef | grep -i zimbra | grep -v grep
[root@proxy1.example.com] #
4. Delete or Remove server from COS
[zimbra@ldap.example.com] $ zmprov ds mta1.example.com
[zimbra@ldap.example.com] $ zmprov ds proxy1.example.com
5. Remove server from Logger Services :
[zimbra@ldap.example.com] $ zmloggerhostmap -d mta1.example.com
[zimbra@ldap.example.com] $ zmloggerhostmap -d proxy1.example.com
This article gives an idea about, How to remove server from server pool ?.